Little W likes rational number $\frac{P}{Q}$ very much. He has n points on the plane. You need to tell him the closest gradient to $\frac{P}{Q}$ of the lines passing through at least two points.

Suppose a line passes through two points $(x_0, y_0)$ and $(x_1, y_1)$. The gradient of it is exactly $g = \frac{y0 - y1}{x0 - x1}$. Closest gradient means $$\mathop{\arg\min} \limits_{g \in G} |g - \frac{P}{Q}|$$ as $G$ is the set of gradients of all availible lines.

### 输入格式

The first lines contain three integers $n, P, Q$. $(5 \leq n \leq 10^6, 1 \leq P, Q \leq 10^5)$

In the following $n$ lines, each line contains two integers $x, y$ represent the coordinate of a point. $(1 \leq x,y \leq 10^9)$

### 输出格式

You should output a rational number $P’$/$Q’$ represents the answer.

We ensure that the answer is unique and larger than 0.

You can use 1/0 to represent the gradient of infinity.

### 样例

Input
6 15698 17433
112412868 636515040
122123982 526131695
58758943 343718480
447544052 640491230
162809501 315494932
870543506 895723090

Output
193409386/235911335


18 人解决，21 人已尝试。

20 份提交通过，共有 61 份提交。

4.6 EMB 奖励。