python怎么处理非常大的数的计算？

‘-999999962927782243 -999999945341416211 -999999903595552532 -999999978590083794’

s_list = list(map(int,input().split(' ')))
x1,y1,x2,y2 = s_list[0],s_list[1],s_list[2],s_list[3]
if y1==y2:
#当为直线时
if abs(x1-x2)%2 == 0:
print(int((x1+x2)/2),y1)
else:
print('NO')
elif x1==x2:
# 当为竖线时
if abs(y1-y2)%2 == 0:
print(x1,int((y1+y2)/2))
else:
print('NO')
else:
if (x1+x2)%2 == 0 and (y1+y2)%2==0:
# 普通情况且中间点为整数
print(int((x1+x2)/2),int((y1+y2)/2))
else:
# 普通情况中间点不为整数
# 通过平移来减小对应的数值
x3 = round((x1+x2)/2)
y3 = round((y1+y2)/2)
x1 = x1-x3
x2 = x2-x3
y1= y1-y3
y2= y2-y3
x5 = (x1+x2)/2
y5 = (y1+y2)/2
# 这个地方可能是隐患，造成的计算不准确,这个地方不是整数，等到后面差异就会变大
a = (x1-x2)/(y1-y2)*-1
b = y5-a*x5
x4 = (x1+x2)//2
ab_len_1 = (x1-x2)*(x1-x2) + (y1-y2)*(y1-y2)
while True:
y4 = a*x4 + b
# ab_len_2 = (x1-x4)*(x1-x4)+(y1-y4)*(y1-y4)
# if int(y4) == y4:
#     ab_len_3 = (x2-x4)*(x2-x4)+(y2-y4)*(y2-y4)
#     if ab_len_2 <= ab_len_1 and ab_len_2==ab_len_3:
#         print(x4+x3,int(y4)+y3)
#         break
#     elif ab_len_2 >= ab_len_1:
#         print('NO')
#         break
# if ab_len_2 >= ab_len_1:
#     print('NO')
#     break
# x4 = x4-1
# continue
y4 = round(y4,4)
ab_len_2 = (x1-x4)*(x1-x4)+(y1-y4)*(y1-y4)
ab_len_3 = (x2-x4)*(x2-x4)+(y2-y4)*(y2-y4)
if ab_len_2 <= ab_len_1:
if int(y4) == y4 and ab_len_2==ab_len_3 :
print(x4+x3,int(y4)+y3)
break
else:
x4 = x4-1
continue
else:
print('NO')
break